Optimal. Leaf size=184 \[ \frac{d (c+d x) \sin (a+b x)}{4 b^2}+\frac{d (c+d x) \sin (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \sin (5 a+5 b x)}{200 b^2}+\frac{d^2 \cos (a+b x)}{4 b^3}+\frac{d^2 \cos (3 a+3 b x)}{216 b^3}-\frac{d^2 \cos (5 a+5 b x)}{1000 b^3}-\frac{(c+d x)^2 \cos (a+b x)}{8 b}-\frac{(c+d x)^2 \cos (3 a+3 b x)}{48 b}+\frac{(c+d x)^2 \cos (5 a+5 b x)}{80 b} \]
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Rubi [A] time = 0.197179, antiderivative size = 184, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {4406, 3296, 2638} \[ \frac{d (c+d x) \sin (a+b x)}{4 b^2}+\frac{d (c+d x) \sin (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \sin (5 a+5 b x)}{200 b^2}+\frac{d^2 \cos (a+b x)}{4 b^3}+\frac{d^2 \cos (3 a+3 b x)}{216 b^3}-\frac{d^2 \cos (5 a+5 b x)}{1000 b^3}-\frac{(c+d x)^2 \cos (a+b x)}{8 b}-\frac{(c+d x)^2 \cos (3 a+3 b x)}{48 b}+\frac{(c+d x)^2 \cos (5 a+5 b x)}{80 b} \]
Antiderivative was successfully verified.
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Rule 4406
Rule 3296
Rule 2638
Rubi steps
\begin{align*} \int (c+d x)^2 \cos ^2(a+b x) \sin ^3(a+b x) \, dx &=\int \left (\frac{1}{8} (c+d x)^2 \sin (a+b x)+\frac{1}{16} (c+d x)^2 \sin (3 a+3 b x)-\frac{1}{16} (c+d x)^2 \sin (5 a+5 b x)\right ) \, dx\\ &=\frac{1}{16} \int (c+d x)^2 \sin (3 a+3 b x) \, dx-\frac{1}{16} \int (c+d x)^2 \sin (5 a+5 b x) \, dx+\frac{1}{8} \int (c+d x)^2 \sin (a+b x) \, dx\\ &=-\frac{(c+d x)^2 \cos (a+b x)}{8 b}-\frac{(c+d x)^2 \cos (3 a+3 b x)}{48 b}+\frac{(c+d x)^2 \cos (5 a+5 b x)}{80 b}-\frac{d \int (c+d x) \cos (5 a+5 b x) \, dx}{40 b}+\frac{d \int (c+d x) \cos (3 a+3 b x) \, dx}{24 b}+\frac{d \int (c+d x) \cos (a+b x) \, dx}{4 b}\\ &=-\frac{(c+d x)^2 \cos (a+b x)}{8 b}-\frac{(c+d x)^2 \cos (3 a+3 b x)}{48 b}+\frac{(c+d x)^2 \cos (5 a+5 b x)}{80 b}+\frac{d (c+d x) \sin (a+b x)}{4 b^2}+\frac{d (c+d x) \sin (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \sin (5 a+5 b x)}{200 b^2}+\frac{d^2 \int \sin (5 a+5 b x) \, dx}{200 b^2}-\frac{d^2 \int \sin (3 a+3 b x) \, dx}{72 b^2}-\frac{d^2 \int \sin (a+b x) \, dx}{4 b^2}\\ &=\frac{d^2 \cos (a+b x)}{4 b^3}-\frac{(c+d x)^2 \cos (a+b x)}{8 b}+\frac{d^2 \cos (3 a+3 b x)}{216 b^3}-\frac{(c+d x)^2 \cos (3 a+3 b x)}{48 b}-\frac{d^2 \cos (5 a+5 b x)}{1000 b^3}+\frac{(c+d x)^2 \cos (5 a+5 b x)}{80 b}+\frac{d (c+d x) \sin (a+b x)}{4 b^2}+\frac{d (c+d x) \sin (3 a+3 b x)}{72 b^2}-\frac{d (c+d x) \sin (5 a+5 b x)}{200 b^2}\\ \end{align*}
Mathematica [A] time = 0.923184, size = 127, normalized size = 0.69 \[ \frac{-6750 \cos (a+b x) \left (b^2 (c+d x)^2-2 d^2\right )-125 \cos (3 (a+b x)) \left (9 b^2 (c+d x)^2-2 d^2\right )+27 \cos (5 (a+b x)) \left (25 b^2 (c+d x)^2-2 d^2\right )+30 b d (c+d x) (450 \sin (a+b x)+25 \sin (3 (a+b x))-9 \sin (5 (a+b x)))}{54000 b^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.026, size = 466, normalized size = 2.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.25098, size = 506, normalized size = 2.75 \begin{align*} \frac{3600 \,{\left (3 \, \cos \left (b x + a\right )^{5} - 5 \, \cos \left (b x + a\right )^{3}\right )} c^{2} - \frac{7200 \,{\left (3 \, \cos \left (b x + a\right )^{5} - 5 \, \cos \left (b x + a\right )^{3}\right )} a c d}{b} + \frac{3600 \,{\left (3 \, \cos \left (b x + a\right )^{5} - 5 \, \cos \left (b x + a\right )^{3}\right )} a^{2} d^{2}}{b^{2}} + \frac{30 \,{\left (45 \,{\left (b x + a\right )} \cos \left (5 \, b x + 5 \, a\right ) - 75 \,{\left (b x + a\right )} \cos \left (3 \, b x + 3 \, a\right ) - 450 \,{\left (b x + a\right )} \cos \left (b x + a\right ) - 9 \, \sin \left (5 \, b x + 5 \, a\right ) + 25 \, \sin \left (3 \, b x + 3 \, a\right ) + 450 \, \sin \left (b x + a\right )\right )} c d}{b} - \frac{30 \,{\left (45 \,{\left (b x + a\right )} \cos \left (5 \, b x + 5 \, a\right ) - 75 \,{\left (b x + a\right )} \cos \left (3 \, b x + 3 \, a\right ) - 450 \,{\left (b x + a\right )} \cos \left (b x + a\right ) - 9 \, \sin \left (5 \, b x + 5 \, a\right ) + 25 \, \sin \left (3 \, b x + 3 \, a\right ) + 450 \, \sin \left (b x + a\right )\right )} a d^{2}}{b^{2}} + \frac{{\left (27 \,{\left (25 \,{\left (b x + a\right )}^{2} - 2\right )} \cos \left (5 \, b x + 5 \, a\right ) - 125 \,{\left (9 \,{\left (b x + a\right )}^{2} - 2\right )} \cos \left (3 \, b x + 3 \, a\right ) - 6750 \,{\left ({\left (b x + a\right )}^{2} - 2\right )} \cos \left (b x + a\right ) - 270 \,{\left (b x + a\right )} \sin \left (5 \, b x + 5 \, a\right ) + 750 \,{\left (b x + a\right )} \sin \left (3 \, b x + 3 \, a\right ) + 13500 \,{\left (b x + a\right )} \sin \left (b x + a\right )\right )} d^{2}}{b^{2}}}{54000 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.505668, size = 406, normalized size = 2.21 \begin{align*} \frac{27 \,{\left (25 \, b^{2} d^{2} x^{2} + 50 \, b^{2} c d x + 25 \, b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (b x + a\right )^{5} - 5 \,{\left (225 \, b^{2} d^{2} x^{2} + 450 \, b^{2} c d x + 225 \, b^{2} c^{2} - 26 \, d^{2}\right )} \cos \left (b x + a\right )^{3} + 780 \, d^{2} \cos \left (b x + a\right ) - 30 \,{\left (9 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{4} - 26 \, b d^{2} x - 26 \, b c d - 13 \,{\left (b d^{2} x + b c d\right )} \cos \left (b x + a\right )^{2}\right )} \sin \left (b x + a\right )}{3375 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 20.5763, size = 382, normalized size = 2.08 \begin{align*} \begin{cases} - \frac{c^{2} \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{3 b} - \frac{2 c^{2} \cos ^{5}{\left (a + b x \right )}}{15 b} - \frac{2 c d x \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{3 b} - \frac{4 c d x \cos ^{5}{\left (a + b x \right )}}{15 b} - \frac{d^{2} x^{2} \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{3 b} - \frac{2 d^{2} x^{2} \cos ^{5}{\left (a + b x \right )}}{15 b} + \frac{52 c d \sin ^{5}{\left (a + b x \right )}}{225 b^{2}} + \frac{26 c d \sin ^{3}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{45 b^{2}} + \frac{4 c d \sin{\left (a + b x \right )} \cos ^{4}{\left (a + b x \right )}}{15 b^{2}} + \frac{52 d^{2} x \sin ^{5}{\left (a + b x \right )}}{225 b^{2}} + \frac{26 d^{2} x \sin ^{3}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{45 b^{2}} + \frac{4 d^{2} x \sin{\left (a + b x \right )} \cos ^{4}{\left (a + b x \right )}}{15 b^{2}} + \frac{52 d^{2} \sin ^{4}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{225 b^{3}} + \frac{338 d^{2} \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{675 b^{3}} + \frac{856 d^{2} \cos ^{5}{\left (a + b x \right )}}{3375 b^{3}} & \text{for}\: b \neq 0 \\\left (c^{2} x + c d x^{2} + \frac{d^{2} x^{3}}{3}\right ) \sin ^{3}{\left (a \right )} \cos ^{2}{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12945, size = 282, normalized size = 1.53 \begin{align*} \frac{{\left (25 \, b^{2} d^{2} x^{2} + 50 \, b^{2} c d x + 25 \, b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (5 \, b x + 5 \, a\right )}{2000 \, b^{3}} - \frac{{\left (9 \, b^{2} d^{2} x^{2} + 18 \, b^{2} c d x + 9 \, b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (3 \, b x + 3 \, a\right )}{432 \, b^{3}} - \frac{{\left (b^{2} d^{2} x^{2} + 2 \, b^{2} c d x + b^{2} c^{2} - 2 \, d^{2}\right )} \cos \left (b x + a\right )}{8 \, b^{3}} - \frac{{\left (b d^{2} x + b c d\right )} \sin \left (5 \, b x + 5 \, a\right )}{200 \, b^{3}} + \frac{{\left (b d^{2} x + b c d\right )} \sin \left (3 \, b x + 3 \, a\right )}{72 \, b^{3}} + \frac{{\left (b d^{2} x + b c d\right )} \sin \left (b x + a\right )}{4 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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